The question
Question: find the size of this matrix.
[2, −1, 0; 5, 3, 7]
A matrix is numbers in rows and columns, inside big brackets.
Each number in a matrix is called an entry.
1 Count the rows
Rows go across.
We count them: 1, 2.
There are 2 rows.
rows = 2
2 Count the columns
Columns go down.
We count them: 1, 2, 3.
There are 3 columns.
columns = 3
The size is rows by columns: 2 by 3.
Rows come first.
We write it like this, and say 2 by 3.
size = 2 × 3
Careful!
Rows always come first, then columns.
3 by 2 would be a different shape.
Careful: not 3 × 2 ✗
3 Check
Let's check.
2 rows of 3 make 2 × 3 = 6 entries.
We count all the entries in the matrix: 6.
So the size is right!
2 × 3 = 6
Let's look back.
First: count the rows.
Then: count the columns.
Last: check.
Answer Careful: not 3 × 2 ✗
▶ Watch it solved
The question
Question: work out this sum of two matrices.
[−2, 5; 3, −1] + [4, −3; −6, 2]
A matrix is numbers in rows and columns, inside big brackets.
Each number in a matrix is called an entry.
1 Check the sizes
Both are 2 by 2: the same size.
Good!
We can only add matrices of the same size, so every entry has a partner in the same place.
2 Add the matching entries
We add the numbers in the same place.
Top left: −2 and 4.
So we write −2 + 4 there.
And the same in every place.
= [−2 + 4, 5 + (−3); 3 + (−6), −1 + 2]
Careful!
We add only the two entries in the same place: top left with top left, and so on.
Careful: only entries in the same place
Now we work out each one.
The answer: rows 2, 2 and −3, 1.
= [2, 2; −3, 1]
3 Check
Let's check by taking away.
The answer minus the second matrix must give back the first one.
2 − 4 = −2, 2 − (−3) = 5
−3 − (−6) = 3, 1 − 2 = −1
We get the first matrix back.
So the answer is right!
Let's look back.
First: check the sizes.
Then: add the matching entries.
Last: check.
▶ Watch it solved
The question
Question: work out this.
2[1, 3; −1, 0] + [4, −2; 5, 1]
A matrix is numbers in rows and columns, inside big brackets.
Each number in a matrix is called an entry.
1 Check the sizes
Both are 2 by 2: the same size.
Good!
We can only add matrices of the same size, so every entry has a partner in the same place.
2 Times first
Like the order of operations: times comes before plus and minus.
2 in front means: every entry times 2.
We write 2 × in front of each one.
= [2 × 1, 2 × 3; 2 × (−1), 2 × 0] + [4, −2; 5, 1]
Now we work out each one.
2 times 1 is 2, and so on.
= [2, 6; −2, 0] + [4, −2; 5, 1]
3 Add the matching entries
We add the numbers in the same place.
Top left: 2 and 4.
So we write 2 + 4 there.
And the same in every place.
= [2 + 4, 6 + (−2); −2 + 5, 0 + 1]
Careful!
We add only the two entries in the same place: top left with top left, and so on.
Careful: only entries in the same place
Now we work out each one.
The answer: rows 6, 4 and 3, 1.
= [6, 4; 3, 1]
4 Check
Let's check by taking away.
The answer minus the second matrix must give back the first one.
6 − 4 = 2, 4 − (−2) = 6
3 − 5 = −2, 1 − 1 = 0
We get the first matrix back, after the times.
So the answer is right!
Let's look back.
First: check the sizes.
Then: times first.
Then: add the matching entries.
Last: check.
▶ Watch it solved