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Solving f

Algebra 2 ยท 20 problems, easy to harder

โ–ถ Watch the first one solved

How we do it

  1. Write the equation
  2. Remove the โˆ’ 3
  3. Remove the 2
  4. Check

The steps for f(x) = 2x - 3, find x when f(x) = 7. Every solution names its steps, so you always know what comes next.

Worked examples

f(x) = 2x - 3, find x when f(x) = 7 Easy

The question

Question: find x when f(x) = 7 for f(x) = 2x โˆ’ 3.

f(x) = 2x โˆ’ 3

f(x) = 7 means: the answer that comes out is 7.

We look for the x that goes in.

f(x) = 7: 7 comes out
find what goes in

Careful!

It is not f(7).

7 is what comes out, not what goes in.

Careful: not f(7) โœ—

1 Write the equation

f(x) is 2x โˆ’ 3.

So 2x โˆ’ 3 = 7.

Now we solve it.

2x โˆ’ 3 = 7

We want x by itself.

Two things are stuck to x: times 2 and โˆ’ 3.

The โˆ’ 3 is on the outside, so it comes off first.

Then the times 2.

2 Remove the โˆ’ 3

To remove โˆ’ 3, we add 3.

We do it on both sides.

Why both sides?

The = sign means both sides are the same amount.

If we change only one side, they are not the same any more.

2x โˆ’ 3 + 3 = 7 + 3

โˆ’ 3 and + 3 make zero.

Cross them out.

7 + 3 = 10.

7 + 3 = 10

Now we have 2x = 10.

2x = 10

3 Remove the 2

2x means 2 times x.

We want just x.

To remove times 2, we divide by 2.

We do it on both sides, so they stay equal.

2x2 = 102

2 divided by 2 is 1.

So just x is left.

10 divided by 2 is 5.

102 = 5

So x = 5!

x = 5

4 Check

Let's check: put 5 into f.

We get 7.

f(5) = 2(5) โˆ’ 3 = 10 โˆ’ 3 = 7

So f(5) = 7.

x = 5 is right!

Let's look back.

First: write the equation.

Then: remove the โˆ’ 3.

Then: remove the 2.

Last: check.

Answer
x = 5

โ–ถ Watch it solved

f(x) = -2x + 5, find x when f(x) = 11 Medium

The question

Question: find x when f(x) = 11 for f(x) = โˆ’2x + 5.

f(x) = โˆ’2x + 5

f(x) = 11 means: the answer that comes out is 11.

We look for the x that goes in.

f(x) = 11: 11 comes out
find what goes in

Careful!

It is not f(11).

11 is what comes out, not what goes in.

Careful: not f(11) โœ—

1 Write the equation

f(x) is โˆ’2x + 5.

So โˆ’2x + 5 = 11.

Now we solve it.

โˆ’2x + 5 = 11

We want x by itself.

Two things are stuck to x: times โˆ’2 and + 5.

The + 5 is on the outside, so it comes off first.

Then the times โˆ’2.

2 Remove the + 5

To remove + 5, we take away 5.

We do it on both sides.

Why both sides?

The = sign means both sides are the same amount.

If we change only one side, they are not the same any more.

โˆ’2x + 5 โˆ’ 5 = 11 โˆ’ 5

+ 5 and โˆ’ 5 make zero.

Cross them out.

11 โˆ’ 5 = 6.

11 โˆ’ 5 = 6

Now we have โˆ’2x = 6.

โˆ’2x = 6

3 Remove the โˆ’2

โˆ’2x means โˆ’2 times x.

We want just x.

To remove times โˆ’2, we divide by โˆ’2.

We do it on both sides, so they stay equal.

โˆ’2xโˆ’2 = 6โˆ’2

โˆ’2 divided by โˆ’2 is 1.

So just x is left.

6 divided by โˆ’2 is โˆ’3.

6โˆ’2 = โˆ’3

So x = โˆ’3!

x = โˆ’3

4 Check

Let's check: put โˆ’3 into f.

We get 11.

f(โˆ’3) = โˆ’2(โˆ’3) + 5 = 6 + 5 = 11

So f(โˆ’3) = 11.

x = โˆ’3 is right!

Let's look back.

First: write the equation.

Then: remove the + 5.

Then: remove the โˆ’2.

Last: check.

Answer
x = โˆ’3

โ–ถ Watch it solved

f(x) = 3x^2 - 2, find x when f(x) = 25 Harder

The question

Question: find x when f(x) = 25 for f(x) = 3xยฒ โˆ’ 2.

f(x) = 3x2 โˆ’ 2

f(x) = 25 means: the answer that comes out is 25.

We look for the x that goes in.

f(x) = 25: 25 comes out
find what goes in

Careful!

It is not f(25).

25 is what comes out, not what goes in.

Careful: not f(25) โœ—

1 Write the equation

f(x) is 3xยฒ โˆ’ 2.

So 3xยฒ โˆ’ 2 = 25.

Now we solve it.

3x2 โˆ’ 2 = 25

2 Get xยฒ alone

There is no x term, so we get xยฒ by itself.

To remove the โˆ’ 2, we add 2 on both sides.

3x2 โˆ’ 2 + 2 = 25 + 2

25 + 2 = 27.

Now we have 3xยฒ = 27.

3x2 = 27

To remove times 3, we divide both sides by 3.

3x23 = 273

27 divided by 3 is 9.

x2 = 9

3 Square root of both sides

x squared is 9.

So x is the square root of 9, or minus it.

Minus times minus is plus, so the negative one works too.

xยฒ = k โ†’ x = โˆšk or x = โˆ’โˆšk
3 ร— 3 = 9, (โˆ’3) ร— (โˆ’3) = 9

3 times 3 is 9.

So x = 3 or x = โˆ’3.

x = 3 or x = โˆ’3

4 Check

Let's check: put 3 into f.

We get 25.

f(3) = 3(3)2 โˆ’ 2 = 27 โˆ’ 2 = 25

And โˆ’3 into f.

We get 25 too.

f(โˆ’3) = 3(โˆ’3)2 โˆ’ 2 = 27 โˆ’ 2 = 25

So f(3) = 25 and f(โˆ’3) = 25.

Both answers are right!

Let's look back.

First: write the equation.

Then: get xยฒ alone.

Then: square root of both sides.

Last: check.

Answer
x = 3 or x = โˆ’3

โ–ถ Watch it solved

Practice

Try each one, then open the answer. Stuck? Open the problem to watch every step.

Easy

  1. f(x) = 2x - 3, find x when f(x) = 7
    Answer
    x = 5
  2. f(x) = 3x + 1, find x when f(x) = 13
    Answer
    x = 4
  3. f(x) = x + 5, find x when f(x) = 2
    Answer
    x = โˆ’3
  4. f(x) = 4x, find x when f(x) = 20
    Answer
    x = 5
  5. f(x) = 5x - 2, find x when f(x) = 8
    Answer
    x = 2
  6. f(x) = 2x + 6, find x when f(x) = 6
    Answer
    x = 0
  7. f(x) = x - 4, find x when f(x) = -1
    Answer
    x = 3
  8. f(x) = 3x + 4, find x when f(x) = -2
    Answer
    x = โˆ’2

Medium

  1. f(x) = -2x + 5, find x when f(x) = 11
    Answer
    x = โˆ’3
  2. f(x) = 3x - 7, find x when f(x) = -1
    Answer
    x = 2
  3. f(x) = 6 - x, find x when f(x) = 9
    Answer
    x = โˆ’3
  4. f(x) = 4x + 3, find x when f(x) = 5
    Answer
    x = 12
  5. f(x) = x^2 - 1, find x when f(x) = 8
    Answer
    x = 3 or x = โˆ’3
  6. f(x) = x^2 + 2, find x when f(x) = 27
    Answer
    x = 5 or x = โˆ’5
  7. f(x) = 2x^2, find x when f(x) = 18
    Answer
    x = 3 or x = โˆ’3

Harder

  1. f(x) = 3x^2 - 2, find x when f(x) = 25
    Answer
    x = 3 or x = โˆ’3
  2. f(x) = 7 - 2x, find x when f(x) = -3
    Answer
    x = 5
  3. f(x) = x^2 - 2x, find x when f(x) = 8
    Answer
    x = โˆ’2 or x = 4
  4. f(x) = 5 - 3x, find x when f(x) = 5
    Answer
    x = 0
  5. f(x) = x^2 + 4, find x when f(x) = 3
    Answer
    x2 = โˆ’1 no real solution