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2, 5, 8, 11, ..., find the 20th term

Step by step, with the reason for every step · Sequences · Algebra 2

Step by step

The question

Question: 2, 5, 8, 11, …: find term 20.

A sequence is a list of numbers in order.

2, 5, 8, 11, ...

1 Find the difference

We add 3 every time.

A list like this is an arithmetic sequence.

The number we add is called the difference: d = 3.

d = 3

2 Find the rule

Term 1 is 2.

a1 = 2

a₁ is term 1, a₂ is term 2.

So aₙ is term number n.

an = term number n

Term 2: we add 3 one time.

a2 = 2 + 1 × 3

Term 3: we add it two times.

a3 = 2 + 2 × 3

We add 3 one time less than the term number.

times we add 3 = term number − 1

So for term n, we add 3, (n − 1) times.

an = 2 + (n − 1) × 3

This rule works for every arithmetic sequence: the first term, plus (n − 1) times the difference.

an = a1 + (n − 1) × d

3 Find term 20

For term 20, n is 20.

We put 20 in place of n.

a20 = 2 + (20 − 1) × 3

Brackets come first.

Order: ( ) → x² √ → × ÷ → + −

20 minus 1 is 19.

= 2 + 19 × 3

Times comes before plus.

19 times 3 is 57.

= 2 + 57

2 plus 57 is 59.

a20 = 59

So term 20 is 59.

4 Check

Let's check the rule with a term we know.

Put n = 4.

a4 = 2 + (4 − 1) × 3 = 2 + 3 × 3 = 2 + 9
= 11

We get 11.

That is term 4 in the list.

So the rule is right!

Let's look back.

First: find the difference.

Then: find the rule.

Then: find term 20.

Last: check.

Answer
a20 = 59

Your turn

Try this one yourself, then check:

8, 10, 12, 14, ... find a17
Show the answer
a17 = 40

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