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6 games, probability of success 40%, probability of exactly 4 wins

Step by step, with the reason for every step · Binomial probability · Probability

Step by step

The question

Question: There are 6 games.

Each one is a success with probability 40%.

What is the probability of exactly 4 successes?

1 Binomial: yes or no

6 games.

Each one has the same chance, and one does not change the next.

Each is a success or not.

That is a binomial experiment.

6 games: same chance, each on its own

n is the number of games: 6.

k is how many successes we want: 4.

p is the chance of a success each time: 0.4.

q is the chance of not: 1 minus p, 0.6.

n = 6 games, k = 4 successes
p = 0.4 (success)
q = 1 − p = 0.6

2 Write the rule

The rule: n C k, times p to the power k, times q to the power n minus k.

P(4 successes) = nCk × pk × qn − k

We put the numbers in.

P(4 successes) = 6C4 × (0.4)4 × (0.6)2

3 Count the orders

6 C 4 counts the orders: which 4 of the 6 games are the successes.

6 times 5 times 4 times 3, over 4 times 3 times 2 times 1, is 15.

6C4 = 6 × 5 × 4 × 34 × 3 × 2 × 1 = 15

4 One order's chance

One order, like this one.

Along one path we multiply: 0.4 for each success, and 0.6 for each failure.

one order = 0.0256 × 0.36
0.4⁴ = 0.0256
0.6² = 0.36

0.0256 times 0.36 is 0.009216.

one order = 0.009216

5 Multiply

Every order has this same chance.

There are 15 orders, so we multiply by 15.

P(4 successes) = 15 × 0.009216

Careful!

That is only one order.

Successes can come in 15 different orders.

Careful: not 0.009216 ✗

15 times 0.009216 is 0.13824.

To 4 decimal places: about 0.1382.

P(4 successes) ≈ 0.1382

6 Check

Let's check: 15 orders, each with the same chance.

So the answer is right!

15 orders × one order's chance

Let's look back.

First: binomial: yes or no.

Then: write the rule.

Then: count the orders.

Then: one order's chance.

Then: multiply.

Last: check.

Answer
P(4 successes) ≈ 0.1382

Your turn

Try this one yourself, then check:

Show the answer
P(3 successes) = 0.0512

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