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95% confidence interval: 642 of 1000 want more parks

Step by step, with the reason for every step · Confidence interval for a proportion · University Statistics

Step by step

The question

Question: in a sample of 1000, 642 want more parks: find the 95% confidence interval for the true proportion.

95% interval for p: 642 of 1000 want more parks

1 Name the numbers

p prime is the part of the sample that says yes: x divided by n.

p′ = the part of the sample: x ÷ n

642 divided by 1000 is 0.642.

p′ = 6421000 = 0.642

q prime is the rest: 1 minus 0.642 is 0.358.

q′ = 1 − 0.642 = 0.358

Careful!

p prime is the fraction 0.642, not the count 642.

Careful: p′ is a part of 1: 642 ÷ 1000, not 642

Both counts, 642 and 358, are at least 5.

So the normal bell works here.

n × p′ = 642, n × q′ = 358: both at least 5

2 Find z*

95 percent of the bell is in the middle.

That leaves 5 percent: 2.5 percent in each end.

95% in the middle: 5% left over, 2.5% in each end

z* marks the cut between the middle and the ends.

Left of z* are the middle and one end: 0.95 plus 0.025 is 0.9750.

left of z* = 0.95 + 0.025 = 0.9750

Now we look for 0.9750 inside the table.

0.9750 is in the table: row 1.9, column .06.

So z = 1.96.

z* = 1.96

3 Error bound

The error bound for a proportion: z* times the square root of p prime times q prime over n.

EBP = z* × √p′ q′n

0.642 times 0.358 is 0.2298.

Divided by 1000: about 0.00022984.

p′ q′n = 0.642 × 0.3581000 = 0.22981000 ≈ 0.00022984

The square root of that is about 0.0152.

√p′ q′n = √0.00022984 ≈ 0.0152

Times 1.96: about 0.0297.

EBP = 1.96 × 0.0152 ≈ 0.0297

4 The interval

Take the error bound away from the middle: 0.642 minus 0.0297 is 0.6123.

= p′ − EBP = 0.642 − 0.0297 = 0.6123

And add it: 0.642 plus 0.0297 is 0.6717.

= p′ + EBP = 0.642 + 0.0297 = 0.6717

The 95 percent confidence interval is (0.6123, 0.6717).

= (0.6123, 0.6717)

5 Say it in words

In words: we are 95 percent confident that the true proportion is between 61.23% and 67.17%.

95% confident: between 61.23% and 67.17%

6 Check

Let's check: the middle of the interval should be 0.642.

0.6123 plus 0.6717, divided by 2, is 0.642.

middle: (0.6123 + 0.6717) ÷ 2 = 0.642

Half the width should be the error bound: 0.6717 minus 0.6123, divided by 2, is 0.0297.

So it is right!

half the width: (0.6717 − 0.6123) ÷ 2 = 0.0297

Let's look back.

First: name the numbers.

Then: find z*.

Then: error bound.

Then: the interval.

Then: say it in words.

Last: check.

Answer
= (0.6123, 0.6717)

Your turn

Try this one yourself, then check:

95% interval for p: 100 of 500 want more parks
Show the answer
(0.1649, 0.2351)

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