Steply

A car worth $20000 loses 15% of its value each year. What is it…

Step by step, with the reason for every step · Exponential growth and decay · Algebra 1

Step by step

The question

Question: A car worth $20000 loses 15% of its value each year.

What is it worth after 3 years?

1 Find the start and the factor

The start is $20000.

Each year it loses 15%.

So 85% is left.

85% is 0.85.

That is the factor.

start: a = $20000
100% − 15% = 85% = 0.85
factor: b = 0.85

2 Write the rule

x is the number of years.

Each year we multiply by 0.85 again.

So y = 20000 × 0.85ˣ.

y = 20000 × 0.85x

Careful!

0.15 is the part that is lost.

We multiply by the part that is left: 0.85.

Careful: not b = 0.15 ✗

3 Put in x = 3

After 3 years, x = 3.

y = 20000 × 0.853

0.85 to the power 3 is 0.614125 (with a calculator).

0.853 = 0.614125

So we multiply 20000 by 0.614125.

= 20000 × 0.614125

So it is $12282.50.

= $12282.50

4 Check

Let's check year by year.

We start at $20000, and multiply by 0.85 each year.

After 3 years we get 12282.5 again.

It works!

after 3 years: 12282.5

Let's look back.

First: find the start and the factor.

Then: write the rule.

Then: put in x = 3.

Last: check.

Answer
= $12282.50

Your turn

Try this one yourself, then check:

Show the answer
$5625

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