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Air flows into a balloon at r(t) = 2t + 10 litres per second. How…

Step by step, with the reason for every step · Net change · Calculus 1

Step by step

The question

Question: Air flows into a balloon at r(t) = 2t + 10 litres per second.

How much flows in from t = 2 to t = 6?

1 The net change

r(t) is a rate: how fast it flows in.

The total that flows in is the integral of the rate, from 2 to 6.

amount = ∫ from 2 to 6 of (2t + 10) dt
amount = ∫ from a to b of r(t) dt

The antiderivative: add 1 to each power, divide by the new power.

Now we have t² + 10t.

= (t2 + 10t) from 2 to 6

Put in 6, then take away the same with 2.

= (62 + 10(6)) − (22 + 10(2))

That is 96 minus 24: 72.

= 96 − 24 = 72

So 72 litres flow in.

amount = 72 litres

Careful!

r is the rate, not the amount.

The amount is the integral of the rate.

Careful: not r(6) − r(2) ✗

2 Check

Let's check with a calculator's integral: about 72.

Right!

calculator: ∫ from 2 to 6 of r(t) dt ≈ 72

Let's look back.

First: the net change.

Last: check.

Answer
Careful: not r(6) − r(2) ✗

Your turn

Try this one yourself, then check:

Show the answer
116 litres

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