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Angle between <6, 8> and <3, 4>

Step by step, with the reason for every step · Dot product, angle between two vectors · Precalculus

Step by step

The question

Question: find the angle between u = ⟨6, 8⟩ and v = ⟨3, 4⟩.

u = ⟨6, 8⟩ and v = ⟨3, 4⟩

1 Find u • v

The dot product: across times across, plus up times up.

u • v = 6 × 3 + 8 × 4

6 times 3 is 18.

8 times 4 is 32.

u • v = 18 + 32

18 plus 32 is 50.

So u • v = 50.

u • v = 50

2 Find the lengths

The length of u: Pythagoras.

36 plus 64 is 100.

The square root is 10.

‖u‖ = √62 + 82 = √100 = 10

The length of v: Pythagoras.

9 plus 16 is 25.

The square root is 5.

‖v‖ = √32 + 42 = √25 = 5

3 Use the angle rule

The rule: cos θ is the dot product over the two lengths multiplied.

cos θ = u • v‖u‖ × ‖v‖

Now put the numbers in: u • v = 50 and the lengths.

cos θ = 5010 × 5

We can make 50/50 simpler.

It is the same as 1.

cos θ = 1

4 Find θ

The cos⁻¹ button turns it back into the angle.

θ = cos−1(1)

Careful!

That number is cos θ, not the angle.

We still need cos⁻¹.

Careful: not θ = 1 ✗

The calculator gives exactly 0.

So θ = 0°.

θ = 0°

5 Check

Does it make sense?

Let's draw u and v.

The arrows point almost the same way: a small angle.

And the dot product is positive, so θ is less than 90°.

0° fits!

u • v > 0 → θ < 90°

Let's look back.

First: find u • v.

Then: find the lengths.

Then: use the angle rule.

Then: find θ.

Last: check.

Answer
θ = 0°

Your turn

Try this one yourself, then check:

Find the angle between u = ⟨4, 3⟩ and v = ⟨8, 6⟩
Show the answer
θ = 0°

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