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Angle sum of a polygon with 20 sides

Step by step, with the reason for every step · Angles in a polygon · Geometry

Step by step

The question

Question: find the sum of the interior angles of a polygon with 20 sides.

1 Cut into triangles

A polygon with 20 sides has 20 sides and 20 corners.

A polygon is a flat shape with straight sides.

Interior angles are the angles inside, at the corners.

Pick one corner.

Draw lines from it to the other corners.

They cut the polygon into 18 triangles.

Each triangle sits on one side of the polygon, away from our corner.

The two sides that touch our corner have no triangle of their own.

So there are 2 fewer triangles than sides: 20 − 2 = 18.

triangles = 20 − 2 = 18

2 Add the triangles

The angles in each triangle add up to 180°.

Together, the triangles make all the angles of the polygon.

18 triangles, 180° each: 18 × 180.

sum = 18 × 180

Forget the zero: 18 times 18 is 324.

Put the zero back: 3240.

18 × 18 = 324 → 3240

Careful: we count the triangles, 18, not the sides, 20.

not 20 × 180!

18 times 180 is 3240.

So the angles add up to 3240°.

sum = 3240°

3 Check

Let's check: 3240 divided by 180 should give the 18 triangles.

3240 ÷ 180 = 18

We get 18 triangles.

So 3240° is right!

Let's look back.

First: cut into triangles.

Then: add the triangles.

Last: check.

Answer
sum = 3240°

Your turn

Try this one yourself, then check:

Find the angle sum: 5 sides.
Show the answer
sum = 540°

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