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Area between y = 4 and y = x^2

Step by step, with the reason for every step · Area between two curves · Calculus

Step by step

The question

Question: find the area between y = 4 and y = x².

y = 4
y = x2

1 Draw the region

Draw both curves.

They cross twice.

The area we want is between the crossings.

2 Where they meet

They meet where the two y's are equal.

4 = x2

Move everything to one side.

x2 − 4 = 0

Factor it.

x² − 4 is a difference of two squares: x² minus 2 squared.

So it is (x − 2)(x + 2).

(x + 2)(x − 2) = 0

So x = −2 or x = 2.

x = −2 or x = 2

3 The top curve

Test a number between −2 and 2: x = 0.

The first gives 4, the second 0.

So y = 4 is on top.

x = 0: 4 > 0

The area between them is shaded.

4 Write the integral

Area between = the integral of the top one minus the bottom one.

area = ∫ from −2 to 2 of ((4) − x2) dx

Careful!

Top minus bottom!

The other way gives a minus answer, −32/3.

Careful: not bottom − top ✗

A minus in front of a bracket changes the sign of every part inside.

Then like terms.

= ∫ from −2 to 2 of (−x2 + 4) dx

5 The antiderivative

The antiderivative: add 1 to each power, divide by the new power.

F(x) = −x33 + 4x

6 Top minus bottom

area = F(2) − F(−2)

Put in 2, then take away the same with −2.

= (−233 + 4(2)) − (−(−2)33 + 4(−2))
= 163 − (−163)

So the area is 32/3 square units.

= 323 square units

7 Check

Let's check F: its derivative is −x² + 4: top minus bottom.

And the area is positive.

Right!

F′(x) = −x2 + 4

Let's look back.

First: draw the region.

Then: where they meet.

Then: the top curve.

Then: write the integral.

Then: the antiderivative.

Then: top minus bottom.

Last: check.

Answer
= 323 square units

Your turn

Try this one yourself, then check:

Find the area between y = x + 2
Show the answer
area = 92 square units

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