Steply

At what point does the graph of f(x) = x^3 + 3x^2 - 2 have a point…

Step by step, with the reason for every step · AP Calculus AB Practice Exam 1 · AP Calculus AB

Step by step

The question

Question: find the concavity and the inflection points of f(x) = x³ + 3x² − 2.

f(x) = x3 + 3x2 − 2

Concave up means the curve bends up, like a cup.

Concave down bends down, like a cap.

f″ is the slope of the slope.

When f″ is positive, the slope keeps growing, so the curve turns up: a cup.

When f″ is negative: a cap.

cup concave up: f″ > 0
cap concave down: f″ < 0

Careful!

Concave up is about the bending, not about going up.

A cup can go down on one side.

Careful: concave up is not "going up"

There are four choices.

First we solve it, the normal way.

Then we pick.

1 Find f″(x)

First f′: the power rule on each term.

f′(x) = 3x^(3 − 1) + 3 × 2x^(2 − 1) + 0

Now we have f′(x) = 3x² + 6x.

= 3x2 + 6x

Then f″: the power rule again, on f′.

f″(x) = 3 × 2x^(2 − 1) + 6 × 1

Now we have f″(x) = 6x + 6.

= 6x + 6

2 Solve f″(x) = 0

The bending can only change where f″ is 0.

So we solve f″(x) = 0.

f″(x) = 0

That is 6x + 6 = 0.

6x + 6 = 0

Take away 6 on both sides, so they stay equal.

6x = −6

Divide by 6: x = −1.

x = −1

3 Sign table for f″

A sign table for f″.

The number −1 cuts the line into 2 parts.

In each part, f″ keeps one sign.

So one test number per part is enough.

Take easy ones: −2, 0.

f″(−2) = 6(−2) + 6 = −12 + 6 = −6
f″(0) = 6(0) + 6 = 0 + 6 = 6

f″(−2) is −6: negative.

So f bends down there: a cap.

cap

f″(0) is 6: positive.

So f bends up there: a cup.

cup
0

4 Inflection points

At x = −1, the bending changes: an inflection point.

infl.

Its y: put −1 into f.

We get 0.

f(−1) = (−1)3 + 3(−1)2 − 2 = −1 + 3 − 2 = 0

f is concave up where f″ is positive: x > −1.

up ∪ : x > −1

f is concave down where f″ is negative: x < −1.

down ∩ : x < −1

And the inflection point is (−1, 0).

inflection : (−1, 0)

5 Check

Let's check with the graph.

A cap, then a cup.

It changes at the inflection point.

Right!

6 Pick the choice

Our answer is concave up: x > −1; concave down: x < −1; inflection: (−1, 0).

That is choice D.

D) (−1, 0)

7 Why not the others

A is (0, −2).

Wrong: f′ = 0 there: a turning point.

A) (0, −2) ✗ f′ = 0 there: a turning point

B is (−2, 2).

Wrong: f′ = 0 there: the other turning point.

B) (−2, 2) ✗ f′ = 0 there: the other turning point

C is (1, 2).

Wrong: solved 6x + 6 = 0 with the wrong sign.

C) (1, 2) ✗ solved 6x + 6 = 0 with the wrong sign

Let's look back.

First: find f″(x).

Then: solve f″(x) = 0.

Then: sign table for f″.

Then: inflection points.

Then: check.

Then: pick the choice.

Last: why not the others.

Answer
inflection : (−1, 0)

Your turn

Try this one yourself, then check your answer:

Find the concavity and the inflection points of f(x) = x3 − 3x2 + 3
Show the answer
concave up: x > 1; concave down: x < 1; inflection: (1, 1)

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