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Average value of f(x) = 9 - x^2 on [0, 3], and find c

Step by step, with the reason for every step · Average value of a function · Calculus 1

Step by step

The question

Question: find the average value of f(x) = 9 − x² on [0, 3], and the number c where f(c) is the average.

f(x) = 9 − x2

1 The formula

The average value: the area under the curve, divided by the width of the interval.

average = 1b − a∫ from a to b of f(x) dx

Here the width is 3 minus 0: 3.

= 13 − 0∫ from 0 to 3 of (9 − x2) dx

Think of it as the height of a rectangle with the same area as under the curve.

average height × width = area

2 The integral

The antiderivative: add 1 to each power, divide by the new power.

Now we have 9x − x³ over 3.

∫ from 0 to 3 of (9 − x2) dx = (9x − x33) from 0 to 3

Put in 3, then take away the same with 0.

= (9(3) − 333) − (9(0) − 033)

That is 18 minus 0: 18.

= 18 − 0 = 18

3 Divide by the width

Divide by the width, 3.

The average value is 6.

average = 183 = 6

Careful!

18 is the area.

To get the average height, divide it by the width, 3.

Careful: not average = 18 ✗

4 Where f(c) is the average

Now find c where f is exactly the average.

f(c) = 6
9 − c2 = 6

Take away 9 on both sides.

−1c2 = −3

Divide by −1.

c2 = 3

Take the square root: c is plus or minus √3, about 1.73.

c = ±√3 ≈ ±1.73

Only c between 0 and 3 counts: c = √3.

c = √3 ≈ 1.73

5 Check

Let's check: a rectangle 6 high and 3 wide has area 18: the same as the integral.

Right!

6 × 3 = 18 = area

In a picture:

the area under the curve,

and the rectangle at the average height.

The same area.

Let's look back.

First: the formula.

Then: the integral.

Then: divide by the width.

Then: where f(c) is the average.

Last: check.

Answer
Careful: not average = 18 ✗

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