Step by step
The question
Question: 2, 3, 5, 8, 12, …: find the rule for term n.
1 First differences
We write the terms in a row.
Under each gap, the jump from one term to the next: 1, 2, 3, 4.
The jumps are not all the same.
So this is not an arithmetic sequence.
2 Second differences
Now the jumps of the jumps: 1 every time.
They are the same.
The same second difference means the rule has n squared in it.
A list like this is a quadratic sequence.
3 Find a
The number in front of n squared is a.
a is half the second difference: 1 divided by 2 is 1/2.
Why half?
Look at n squared itself: 1, 4, 9, 16.
The jumps are 3, 5, 7, and their jumps are 2.
So n squared gives a second difference of 2.
Careful!
a is not the second difference itself.
It is half of it.
4 Take away 1 over 2n²
A table: n is the term number.
Under each term: 1/2 times n squared.
1/2, 2, 9/2 and so on.
Take it away from each term.
What is left: 3/2, 1, 1/2, 0, −1/2.
5 The linear part
What is left goes up by −1/2 each time: an arithmetic sequence.
Its first term is 3/2.
The arithmetic rule: the first term, plus (n − 1) times the difference.
Open the bracket and put the plain numbers together: −1/2n + 2.
6 Put it together
The rule is 1/2, times n squared, minus 1/2, times n + 2.
7 Check
Let's check the rule with n = 1, 2 and 3.
We get 2, 3, 5: the first terms of the list.
So the rule is right!
Let's look back.
First: first differences.
Then: second differences.
Then: find a.
Then: take away 1/2n².
Then: the linear part.
Then: put it together.
Last: check.