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Calculate 2u + v for u = (3, -2), v = (-1, 5)

Step by step, with the reason for every step · Linear combinations · Linear Algebra

Step by step

The question

Question: work out 2u + v.

u = [3; −2]
v = [−1; 5]

u is (3, −2), and v is (−1, 5).

We put them in.

So 2u + v is this.

= 2 × [3; −2] + [−1; 5]

A vector in R 2 is a column of 2 numbers.

Numbers times vectors, added together, is called a linear combination.

a vector in R²: a column of 2 numbers
linear combination: numbers × vectors, added

1 Multiply each vector by its number

Each vector is multiplied by its number: every entry.

2 × 3 at the top, and so on down.

= [2 × 3; 2 × (−2)] + [−1; 5]

We work out each times.

= [6; −4] + [−1; 5]

2 Add matching entries

Now matching entries go together: top with top, then the next, down to the bottom.

= [6 + (−1); −4 + 5]

Careful!

Every entry gets the same treatment.

Top with top, second with second, down to the bottom.

Careful: every entry: top with top, down to the bottom

So the answer is the vector (5, 1).

= [5; 1]

3 Check

Let's check.

We take the second part away from the answer.

The first part must come back.

= [5; 1] − [−1; 5]
= [5 − (−1); 1 − 5]
= [6; −4]

We get (6, −4): that is 2 × u, the first part.

So the answer is right!

Let's look back.

First: multiply each vector by its number.

Then: add matching entries.

Last: check.

Answer
= [5; 1]

Your turn

Try this one yourself, then check:

3u + v for u = [2; −1], v = [−1; 4]
Show the answer
[5; 1]

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