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Calculate gcd(252, 198) by Euclid's algorithm

Step by step, with the reason for every step · Euclid's algorithm · Discrete Math

Step by step

The question

Question: find gcd(252, 198) by Euclid's algorithm.

gcd(252, 198)

1 Divide the bigger by the smaller

Divide the bigger number by the smaller: 198 goes into 252 once, and 54 is left over.

252 = 1 × 198 + 54

Here is the trick.

A number that goes into 252 and 198 also goes into 54, because 54 is 252 minus 1 × 198.

So the gcd does not change, and the numbers get smaller.

gcd(252, 198) = gcd(198, 54)

2 Keep going

Now the same with 198 and 54: the divisor moves left, the remainder becomes the new divisor.

198 = 3 × 54 + 36

54 = 1 × 36 + 18.

54 = 1 × 36 + 18

36 = 2 × 18, and the remainder is 0.

We stop.

36 = 2 × 18 + 0

3 The last remainder before 0

Careful!

0 only tells us to stop.

The answer is the last remainder before it: 18.

Careful: not gcd(252, 198) = 0 ✗

The last remainder that is not 0 is 18.

So gcd(252, 198) = 18.

gcd(252, 198) = 18

4 Check

18 goes into both: 252 ÷ 18 is 14, and 198 ÷ 18 is 11.

252 ÷ 18 = 14, 198 ÷ 18 = 11

And 14 and 11 have no common factor, so nothing bigger than 18 goes into both.

Right!

14 and 11: no common factor

Let's look back.

First: divide the bigger by the smaller.

Then: keep going.

Then: the last remainder before 0.

Last: check.

Answer
gcd(252, 198) = 18

Your turn

Try this one yourself, then check:

gcd(250, 195)
Show the answer
gcd(250, 195) = 5

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