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Chi-square goodness of fit: observed 12, 18, 30, 40; expected 10%…

Step by step, with the reason for every step · Chi-square · University Statistics

Step by step

The question

Question: we saw the counts 12, 18, 30, 40, and expected 10%, 20%, 30%, 40%: at the 5% level, do the data fit?

observed 12, 18, 30, 40; expected 10%, 20%, 30%, 40%; α = 0.05

1 Write the hypotheses

H₀ is the "nothing new" idea.

Here: the data fit the expected parts.

H0 : the data fit the expected parts

Hₐ is what we want to show.

Here: the data do not fit.

Ha : the data do not fit

2 Expected counts

If H zero is true, each cell expects n times its part.

E = n × p (if H0 is true)

A: 100 times 0.1 is 10.

E(A) = 100 × 0.1 = 10

B: 100 times 0.2 is 20.

E(B) = 100 × 0.2 = 20

C: 100 times 0.3 is 30.

E(C) = 100 × 0.3 = 30

D: 100 times 0.4 is 40.

E(D) = 100 × 0.4 = 40

Every expected count is at least 5, so the test works.

all E at least 5: the test works

3 Each part

Chi-square adds up, for each cell, the observed minus the expected, squared, over the expected.

χ2 = add up all (O − E)2E

A table: each cell, what we saw, O, and what we expected, E.

12 minus 10 is 2.

Squared, 4.

Over 10: 0.4.

18 minus 20 is −2.

Squared, 4.

Over 20: 0.2.

30 minus 30 is 0.

Squared, 0.

Over 30: 0.

40 minus 40 is 0.

Squared, 0.

Over 40: 0.

Careful!

We always divide by the expected count, not the observed one.

Careful: divide by E (expected), not by O

4 Add them

0.4 plus 0.2 plus 0 plus 0 is 0.6.

χ2 = 0.4 + 0.2 + 0 + 0 = 0.6

5 The cut-off

df is the number of cells minus 1: 4 minus 1 is 3.

df = k − 1 = 4 − 1 = 3

Chi-square is always a right-tail test: big means far from what we expected.

Row 3, column 0.05.

Row 3, column .05: the cut-off is 7.815.

6 Decide

The chi-square curve for df 3.

Past the cut-off, 7.815, is the reject part.

0.6 is not past the cut-off.

So we do not reject H zero.

= χ2 = 0.6 < 7.815 → do not reject H0

7 Say it in words

At the 5% level, there is not enough evidence that

In words: at the 5% level, there is not enough evidence that the data do not fit.

the data do not fit.

This does not prove H zero is true.

We just cannot rule it out.

not rejecting H0 does not prove H0

8 Check

Let's check: the expected counts add up to 100, like the observed ones.

E: 10 + 20 + 30 + 40 = 100 = n

And the differences O minus E add up to 0.

So it is right!

O − E: 2 + (−2) + 0 + 0 = 0

Let's look back.

First: write the hypotheses.

Then: expected counts.

Then: each part.

Then: add them.

Then: the cut-off.

Then: decide.

Then: say it in words.

Last: check.

Answer
= χ2 = 0.6 < 7.815 → do not reject H0

Your turn

Try this one yourself, then check:

observed 18, 40, 12, 30; expected 20%, 40%, 10%, 30%; α = 0.05
Show the answer
do not reject H0

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