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Coordinates of (6, 4) in the basis (1, 1), (2, 0)

Step by step, with the reason for every step · Basis and coordinates · Linear Algebra

Step by step

The question

Question: find the coordinates of (6, 4) in the basis (1, 1) and (2, 0).

b1 = [1; 1], b2 = [2; 0]

We call the basis vectors b₁ and b₂, in this order, and the vector v.

v = [6; 4]

The coordinates of v are the numbers that make v from the basis vectors, in the basis order.

coordinates: the numbers c1, ..., c2 in
v = c1b1 + c2b2

1 Write the vector equation

We look for c₁ and c₂.

c1[1; 1] + c2[2; 0] = [6; 4]

2 Write the augmented matrix

Each vector goes in as a column: the first entries make row 1, the second entries row 2.

v goes after the bar.

= [1, 2, 6; 1, 0, 4]

We call the rows R 1 and R 2.

3 Row reduce

We use the three row moves: swap two rows, times a row by a number that is not 0, add a multiple of one row to another.

They never change the answers.

Our goal: a leading 1 in each row, with 0s above and below it.

swap two rows
× a row by a number (not 0)
add a multiple of one row to another
→ [1, 2, 6; 0, −2, −2]
→ [1, 2, 6; 0, 1, 1]
→ [1, 0, 4; 0, 1, 1]

4 Read the coordinates

Each row is an equation again.

Row 1: c₁ = 4.

c1 = 4

Row 2: c₂ = 1.

c2 = 1

We write them as a column, in the basis order: (4, 1).

[v]B = [4; 1]

Careful!

The order follows the basis.

c₁ goes with b₁, so it comes first.

Careful: not (1, 4) ✗

5 Check

Let's check: 4b₁ + b₂ must give v.

= 4 × [1; 1] + [2; 0]
= [4 × 1; 4 × 1] + [2; 0]
= [4; 4] + [2; 0]
= [4 + 2; 4 + 0]
= [6; 4]

We get (6, 4): that is v.

So the answer is right!

Let's look back.

First: write the vector equation.

Then: write the augmented matrix.

Then: row reduce.

Then: read the coordinates.

Last: check.

Answer
Careful: not (1, 4) ✗

Your turn

Try this one yourself, then check:

Coordinates of [8; 2] in the basis [1; 1], [2; 0]
Show the answer
[v]B = [2; 3]

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