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Cups cost $4 and plates cost $6. Ben can spend at most $50. Can he…

Step by step, with the reason for every step · Two things, one total · Algebra 1

Step by step

The question

Question: Cups cost $4 and plates cost $6.

Ben can spend at most $50.

Can he buy 5 cups and 6 plates?

1 Find what we know

What do we know?

Cups cost $4 each.

Plates cost $6 each.

Ben can spend $50 or less.

What do we want?

To know if 5 cups and 6 plates fit.

2 Name the unknowns

We don't know how many cups.

We call that number x.

x = number of cups

We don't know how many plates either.

It is a different number, so it gets its own letter: y.

y = number of plates

3 Write the inequality

One cup costs $4.

So x cups cost 4 times x: 4x.

x cups: 4 × x = 4x

One plate costs $6.

So y plates cost 6 times y: 6y.

y plates: 6 × y = 6y

At most $50 means $50 or less.

That is the sign less than or equal to.

at most $50 = $50 or less: ≤

In words: the cup money plus the plate money is at most $50.

4x + 6y = 50

So the inequality is 4x + 6y ≤ 50.

4x + 6y ≤ 50

Careful!

At most means 50 or less.

So the sign is less than or equal to, not more than.

Careful: not 4x + 6y ≥ 50 ✗

4 Put the point in

5 cups: x = 5.

6 plates: y = 6.

As a point, that is (5, 6).

x = 5 , y = 6 (5, 6)

We put them in.

Is it less than or equal to 50?

We don't know yet.

4 × 5 + 6 × 6 ≤? 50

4 times 5 is 20.

6 times 6 is 36.

4 × 5 = 20
6 × 6 = 36

20 plus 36 is 56.

20 + 36 ≤? 50

Is 56 less than or equal to 50?

No.

That is false.

56 > 50 false ✗

5 Answer the question

No: 5 cups and 6 plates cost $56.

6 Check

Let's check with the money.

Ben would need $6 more.

So Ben can't.

It works!

$56 − $50 = $6 too much

Let's look back.

First: find what we know.

Then: name the unknowns.

Then: write the inequality.

Then: put the point in.

Then: answer the question.

Last: check.

Answer
56 > 50 false ✗

Your turn

Try this one yourself, then check:

Show the answer
No, $102

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