Steply

d/dx ∫ from x to 5 of cos(t) dt

Step by step, with the reason for every step · The Fundamental Theorem, part 1 · Calculus 1

Step by step

The question

Question: find the derivative of ∫ from x to 5 of cos t dt.

ddx∫ from x to 5 of cos t dt =

1 The rule

The rule: the derivative of the area from a to x is the function at x.

Just put x in place of t.

ddx∫ from a to x of f(t) dt = f(x)

2 Swap the limits

x is at the bottom.

Swap the limits: swapping them flips the sign.

ddx∫ from x to 5 of cos t dt = −ddx∫ from 5 to x of cos t dt

Careful!

x is the bottom limit here.

Swapping the limits gives a minus sign.

Do not lose it.

Careful: not answer cos x (no minus) ✗

3 Put x in place of t

Put x in place of t.

So the derivative is −cos x.

= −cos x

4 Check

Let's check at x = 6.

Our answer gives −0.9602, in radians.

answer at x = 6: −0.9602

Now the slope of the area function F between x = 6 and 6.001, with a calculator: about −0.96.

The same!

Right!

F(6.001) − F(6)0.001 ≈ −0.96

Let's look back.

First: the rule.

Then: swap the limits.

Then: put x in place of t.

Last: check.

Answer
= −cos x

Your turn

Try this one yourself, then check:

ddx∫ from x to 5 of 2 cos t dt
Show the answer
−2cos x

More from The Fundamental Theorem, part 1

The whole lesson: The Fundamental Theorem, part 1 →