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Derivative of 2√x + 3x

Step by step, with the reason for every step · The power rule · Calculus

Step by step

The question

Question: find the derivative of f(x) = 2 √x + 3x.

f(x) = 2√x + 3x

1 The rule

From the definition we found: x² gives 2x, and x³ gives 3x².

x2 → 2x
x3 → 3x2

See the pattern?

The power comes down in front, and the power goes down by 1.

This is the power rule.

ddxxn = nxn − 1

We write the derivative as f′(x), "f prime of x".

f′(x): the derivative of f(x)

2 Write as powers

To use the rule, every x needs a power.

f(x) = 2x^(1/2) + 3x

A square root is the power one half.

√x = x^(1/2)

3 Each term

Use the rule on each term.

A number in front just waits, and multiplies.

f′(x) = 2 × 12x^(1/2 − 1) + 3 × 1

Take 1 away from the power: 1/2 − 1 = −1/2.

12 − 1 = −12

Work out each one.

= x^(−1/2) + 3

4 Tidy up

Books write it without minus or fraction powers.

So f′(x) = 1 over √x + 3.

= 1√x + 3

5 Check

Let's check: the derivative is the slope.

At x = 1, the rule gives 4.

f′(1) = 1 + 3 = 4

Now the slope between two very close points: x = 1 and x = 1.001.

A calculator gives about 4.

Very close to 4.

Right!

f(1.001) − f(1)0.001 ≈ 4

Let's look back.

First: the rule.

Then: write as powers.

Then: each term.

Then: tidy up.

Last: check.

Answer
= 1√x + 3

Your turn

Try this one yourself, then check:

Find the derivative of f(x) = 3√x + 3x
Show the answer
f′(x) = 32√x + 3

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