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Derivative of 2tan^-1(x)

Step by step, with the reason for every step · Derivatives of inverse trig functions · Calculus 1

Step by step

The question

Question: find the derivative of f(x) = 2tan⁻¹ x.

f(x) = 2tan⁻¹ x

1 The rule

y = tan⁻¹ x means: tan y = x.

y is the angle whose tangent is x.

y = tan⁻¹ x means tan y = x

Take the derivative of both sides: sec² y times y′ is 1.

So y′ is 1 over sec² y, which is 1/1 plus tan² y: 1/1 plus x².

sec²y × y′ = 1
y′ = 1sec²y = 11 + tan²y = 11 + x²

The rule: the derivative of tan⁻¹ x is 1/(1 + x²).

tan⁻¹ x → 11 + x²

Careful!

The little −1 means the inverse function, the angle.

It does not mean 1 over tan x.

Careful: tan⁻¹ x is not 1tan x

2 Use the rule

The 2 in front just waits, and multiplies.

f′(x) = 2 × 11 + x²

So f′(x) = 2/(1 + x²).

= 21 + x²

3 Check

Let's check: the derivative is the slope.

At x = 1, our answer gives 1, with a calculator in radians.

f′(1) = 1

Now the slope between two very close points: x = 1 and x = 1.001.

A calculator gives about 1.

Very close to 1.

Right!

f(1.001) − f(1)0.001 ≈ 1

Let's look back.

First: the rule.

Then: use the rule.

Last: check.

Answer
= 21 + x²

Your turn

Try this one yourself, then check:

Find the derivative of f(x) = 5tan⁻¹ x
Show the answer
f′(x) = 51 + x²

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