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Derivative of 3e^(x^2 + 1)

Step by step, with the reason for every step · Derivatives of sin, cos, e and ln · Calculus

Step by step

The question

Question: find dy/dx for y = 3e^(x² + 1).

y = 3e^(x² + 1)

1 The inside

There is something inside: x² + 1.

Call it u.

u = x2 + 1

Then y is just 3eu.

y = 3eu

2 The outside

eˣ is special: its derivative is itself.

Its slope always equals its height.

ex → ex

First the outside.

The rule on 3eu gives 3eu.

dydu = 3eu

3 The inside's slope

Now the inside.

The power rule on x² + 1 gives 2x.

dudx = 2x

4 Multiply

The chain rule: multiply the two.

dy/du times du/dx.

dydx = dydu × dudx

Put the inside back in place of u.

= 3e^(x² + 1) × 2x

Careful!

Do not stop here!

We must multiply by the inside's slope, 2x.

Careful: not 3e^(x² + 1) ✗
3 × 2x = 6x

Write the numbers in front.

So dy/dx = 6x e^(x² + 1).

= 6x e^(x² + 1)

5 Check

Let's check: the derivative is the slope.

At x = 1, the rule gives 44.3343, with a calculator.

dy/dx at x = 1: 44.3343

Now the slope between two very close points: x = 1 and x = 1.001.

A calculator gives about 44.4.

Very close to 44.3343.

Right!

y(1.001) − y(1)0.001 ≈ 44.4

Let's look back.

First: the inside.

Then: the outside.

Then: the inside's slope.

Then: multiply.

Last: check.

Answer
= 6x e^(x² + 1)

Your turn

Try this one yourself, then check:

Find dy/dx for y = 2e^(x² + 1)
Show the answer
dydx = 4x e^(x² + 1)

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