Step by step
The question
Question: find f′(x) for f(x) = x² − 4x, from the definition, and the slope at x = 2.
1 The idea
Look at the curve y = x² − 4x.
Take a point P on it.
How steep is the curve at P?
Take a second point Q, a little to the right: x + h.
Here h = 1.
The line through P and Q has slope rise over run.
The run is h.
Move Q closer: h = ½.
The line turns.
It gets closer to the curve's own steepness.
When h goes to 0, the line just touches the curve at P.
It is called the tangent.
Its slope is the derivative.
Written as a rule: the rise is f(x + h) minus f(x).
The run is h.
Then h goes to 0.
2 Find f(x + h)
Put x + h in place of x, in brackets.
(x + h)² means (x + h) times (x + h).
Open it: x² + 2xh + h².
Careful!
The 2xh in the middle must not be lost.
What is in front of a bracket multiplies every part inside.
Now we have x² + 2xh + h² − 4x − 4h.
3 Take away f(x)
Now take away f(x).
It goes in brackets: − (x² − 4x).
A minus in front of a bracket changes the sign of every part inside.
Every term of f(x) meets its opposite.
They make zero: cross them out.
Write what is left.
Every term left has an h.
4 Divide by h
Divide by the run, h.
Every term on top has an h, so take it out: 2xh + h² − 4h is h(2x + h − 4).
h is close to 0, but not 0.
So h/h is 1.
Cross them out.
Write what is left.
5 Let h go to 0
Now let h go to 0.
Every term with an h becomes 0.
Cross them out.
So the derivative is f′(x) = 2x − 4.
6 The slope at x = 2
Put 2 in.
The slope at x = 2 is 0.
7 Check
From P, go right 1.
The slope is 0: no going up.
We stay on the flat tangent.
Right!
Let's look back.
First: the idea.
Then: find f(x + h).
Then: take away f(x).
Then: divide by h.
Then: let h go to 0.
Then: the slope at x = 2.
Last: check.