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Discriminant of 2x^2 - 7x + 3 = 0

Step by step, with the reason for every step · The discriminant · Algebra 1

Step by step

The question

Question: find the number of real solutions of 2x² − 7x + 3 = 0.

2x2 − 7x + 3 = 0

1 Find a, b and c

We read the numbers: a = 2 is with x², b = −7 is with x, c = 3 is the plain number.

a = 2, b = −7, c = 3

2 Work out b² − 4ac

In the formula, b² − 4ac is under the square root.

It is called the discriminant.

Its sign tells us how many solutions there are.

x = −b ± √b2 − 4ac2a

We put the numbers in, each negative one in brackets.

b2 − 4ac = (−7)2 − 4 × 2 × 3

(−7)² is 49.

Minus times minus is plus.

4 times 2 times 3 is 24.

(−7)² = (−7) × (−7) = 49
4 × 2 × 3 = 24

Careful!

b = −7 goes in brackets.

(−7) squared is 49, not minus 49.

Careful: not −7² = −49 ✗

So we have 49 take away 24.

= 49 − 24

So the discriminant is 25.

= 25

3 How many solutions

25 is positive.

The square root of a positive number is a real number.

The plus or minus gives two different answers.

positive → 2 real solutions
0 → 1 real solution
negative → no real solutions

So 2x² − 7x + 3 = 0 has 2 real solutions.

= 2 real solutions

4 Check

Let's check with the formula.

Under the root we get 25.

Its square root is 5.

x = 7 ± 54

The plus gives 3, the minus gives 1/2.

Two different solutions.

It works!

x = 3 or 12

Let's look back.

First: find a, b and c.

Then: work out b² − 4ac.

Then: how many solutions.

Last: check.

Answer
= 2 real solutions

Your turn

Try this one yourself, then check:

Find the number of real solutions of 4x2 − 6x − 4 = 0
Show the answer
2 real solutions

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