Steply

Distance-time graph: (0, 0) (1, 45) (2, 45) (4, 45) (5, 0), find the…

Step by step, with the reason for every step · Distance-time graphs · Algebra 1

Step by step

The question

Question: the distance-time graph joins (0, 0) (1, 45) (2, 45) (4, 45) (5, 0), find the average speed.

distance-time graph: (0, 0) (1, 45) (2, 45) (4, 45) (5, 0)

1 Read the graph

Across: the time in hours.

Up: how far from the start, in km.

Going up: moving away from the start.

Flat: stopped.

Going down: coming back.

2 Total distance and time

Add up how far it went in each part, going and coming back: 90 km.

Flat parts add nothing.

total distance = 45 + 45 = 90 km

The whole trip took 5 h, stops too.

total time = 5 h

Careful!

The time when it stopped is part of the trip.

It goes in the total time.

Careful: the stops count in the time

3 Average speed

Average speed is the total distance divided by the total time: 18 km/h.

average speed = 905 = 18 km/h

4 Check

Let's check: 18 times 5 gives back the total distance, 90.

So it is right!

18 × 5 = 90

Let's look back.

First: read the graph.

Then: total distance and time.

Then: average speed.

Last: check.

Answer
average speed = 905 = 18 km/h

Your turn

Try this one yourself, then check:

distance-time graph: (0, 0) (1, 90) (2, 90) (4, 90) (5, 0)
Show the answer
average speed = 36 km/h

More from Distance-time graphs

The whole lesson: Distance-time graphs →