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Divide (x^2 + 7x + 10) ÷ (x + 5)

Step by step, with the reason for every step · Dividing polynomials · Algebra 2

Step by step

The question

Question: divide (x² + 7x + 10) by (x + 5).

x2 + 7x + 10x + 5

1 Set it up

We write it like long division with numbers.

x + 5 goes outside, x² + 7x + 10 inside.

2 First part of the answer

Divide the first parts: x² divided by x is x.

We write it on top.

Multiply: x times (x + 5) is x² + 5x.

We write it under, with a minus: we take it away.

x² take away x² is 0.

That is why we chose x.

7x take away 5x is 2x.

Bring down the next part: 10.

3 Second part of the answer

Divide the first parts: 2x divided by x is 2.

We write it on top.

Multiply: 2 times (x + 5) is 2x + 10.

We write it under, with a minus: we take it away.

2x take away 2x is 0.

That is why we chose 2.

10 take away 10 is 0.

The last part is 0.

So nothing is left over.

So the answer is x + 2.

Nothing is left over.

x2 + 7x + 10x + 5 = x + 2

4 Check

Let's check with a number: x = 2.

First the start: x² + 7x + 10.

Start: 22 + 7(2) + 10 = 4 + 14 + 10 = 28

Now the answer: (x + 5) times (x + 2).

Answer: (2 + 5) × (2 + 2) = (7) × (4) = 28

Both give 28.

So the answer is right!

Both give 28

Let's look back.

First: set it up.

Then: first part of the answer.

Then: second part of the answer.

Last: check.

Answer
x2 + 7x + 10x + 5 = x + 2

Your turn

Try this one yourself, then check:

x2 + 6x + 9x + 3
Show the answer
x2 + 6x + 9x + 3 = x + 3

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