Steply

Does Σ 1/n^4 converge

Step by step, with the reason for every step · The integral test and p-series · Calculus 2

Step by step

The question

Question: decide if the series converges: the sum of 1/n⁴ for n from 1 to infinity.

Σn = 1∞1n4 =

1 The function

Make a function from the term: put x in place of n.

The series adds f(1), f(2), f(3) and so on.

f(x) = 1x4

For x from 1 on, it is positive, and it gets smaller: a bigger x makes a bigger bottom.

x ≥ 1: f(x) > 0, getting smaller

The integral test: the series and the area under f from 1 to infinity do the same thing.

Both are finite, or both are infinite.

Σ and ∫ from 1 to ∞: both finite, or both ∞

2 The integral

Infinity is not a number: stop at t, then let t grow, like improper integrals.

∫ from 1 to ∞ of 1x4 dx = lim t → ∞ ∫ from 1 to t of 1x4 dx

The power rule: add 1 to the power, divide by the new power.

= lim t → ∞ [ −13x3 ] from 1 to t

3 Let t go

Put in t, then take away the same with 1.

= lim t → ∞ (−13t3 − (−13))

As t grows, this part goes to 0.

−13t3 → 0

So the area is 1/3: a number.

= 13

4 Decide

The area is finite, so the series converges too.

= converges

This gives a rule for every power of n: the p-series rule.

Here p is 4, bigger than 1.

p-series: Σ 1np converges when p > 1
and diverges when p ≤ 1

Careful!

The area tells us only that the series converges.

The sum itself is a different number.

Careful: not the sum is 1 over 3 ✗

5 Check

Let's check with a calculator: the first 1000 terms add up to about 1.082.

It stays below the first term plus the area, 1.333.

It settles.

Right!

S1000 ≈ 1.082 < a1 + area = 1.333

Let's look back.

First: the function.

Then: the integral.

Then: let t go.

Then: decide.

Last: check.

Answer
= converges

Your turn

Try this one yourself, then check:

Σn = 1∞5n^(5/2)
Show the answer
converges

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