Steply

Does Σ (4n^2 - n)/(2n^2 + 5) converge

Step by step, with the reason for every step · The divergence test · Calculus 2

Step by step

The question

Question: decide if the series converges: the sum of (4n² − n)/(2n² + 5) for n from 1 to infinity.

Σn = 1∞4n2 − n2n2 + 5 =

1 The term

A series adds up the terms aₙ for ever.

First look at one term, (4n² − n)/(2n² + 5).

an = 4n2 − n2n2 + 5

The divergence test: if the terms do not go to 0, adding them for ever never settles.

The series diverges.

divergence test:
if an does not → 0,
the series diverges

2 The limit

Divide top and bottom by n to the 2, the highest power at the bottom.

an = 4 − 1n2 + 5n2

Every part with n at the bottom goes to 0.

as n → ∞ = 4 − 02 + 0

So the terms go to 2.

= 2

3 Decide

The terms do not go to 0.

Adding numbers close to 2 for ever never settles: the series diverges.

= diverges

Careful!

2 is where each term ends up, not the sum.

The sum grows by about 2 every time.

Careful: not the sum is 2 ✗

4 Check

Let's check with a calculator: the sums of the first 10, 100, 1000 terms are 15.57, 194.02, 1992.83.

They keep growing.

Right!

S₁₀ ≈ 15.57, S₁₀₀ ≈ 194.02, S₁₀₀₀ ≈ 1992.83

Let's look back.

First: the term.

Then: the limit.

Then: decide.

Last: check.

Answer
= diverges

Your turn

Try this one yourself, then check:

Σn = 1∞4n2 − 3n3n2 + 4
Show the answer
diverges

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