Steply

Does Σ 5^n/n! converge

Step by step, with the reason for every step · The ratio and root tests · Calculus 2

Step by step

The question

Question: decide if the series converges: the sum of 5ⁿ over n factorial for n from 1 to infinity.

Σn = 1∞5nn! =

1 The next term

The ratio test: divide each term by the one before it, and let n grow.

If the limit L is less than 1, the terms shrink like a geometric series: it converges.

Bigger than 1: it diverges.

Exactly 1: the test cannot tell.

ratio test: L = lim an+1an
L < 1 converges, L > 1 diverges

The next term: put n + 1 wherever there is an n.

an+1 = 5n+1(n + 1)!

2 The ratio

Dividing by aₙ is the same as times its flip.

an+1an = 5n+1(n + 1)! × n!5n

Group the same kinds together.

5 to the n + 1, over 5 to the n, is just 5.

(n + 1) factorial is n + 1 times n factorial, so their fraction is 1/n + 1.

= 5 × 1n + 1
bn+1 ÷ bn = b
(n + 1)!n! = n + 1

Careful!

(n + 1) factorial is n + 1 times n factorial.

So the fraction is n + 1, not 1.

Careful: not (n + 1)!n! = 1 ✗

3 The limit

As n grows: 1/n + 1 goes to 0.

So L = 0.

L = 0

4 Decide

L = 0 is less than 1: the series converges.

= converges

5 Check

Let's check with a calculator: 10, 20, 50 terms add up to 145.3806, 147.4131, 147.4132.

It settles.

Right!

S10 ≈ 145.3806, S20 ≈ 147.4131, S50 ≈ 147.4132

Let's look back.

First: the next term.

Then: the ratio.

Then: the limit.

Then: decide.

Last: check.

Answer
= converges

Your turn

Try this one yourself, then check:

Σn = 1∞nn!
Show the answer
converges

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