Steply

Double integral of 2x over 0 ≤ x ≤ 3, 0 ≤ y ≤ 2

Step by step, with the reason for every step · Double integrals over rectangles · Calculus 3

Step by step

The question

Question: find the double integral of 2x/0 ≤ x ≤ 3, 0 ≤ y ≤ 2.

∫ ∫ 2x dA, 0 ≤ x ≤ 3, 0 ≤ y ≤ 2

1 Draw it

The rectangle lies on the floor: x from 0 to 3, y from 0 to 2.

Above it is the surface z = 2x.

The double integral is the volume of this solid.

2 Find the limits

Write it as two integrals.

Inside: y from 0 to 2.

Outside: x from 0 to 3.

∫ ∫ 2x dA = ∫ from 0 to 3 of ∫ from 0 to 2 of 2x dy dx

Careful!

The inside integral is dy, so its limits are the y limits.

They may have x in them.

The outside limits are only numbers.

Careful: dy inside: the y limits go inside

3 The inner integral

Inside first: integrate in y.

x stays fixed, like a plain number.

Integrate each term: the power goes up by 1, and we divide by the new power.

∫ from 0 to 2 of 2x dy = 2xy from 0 to 2

Put in the top y = 2, then take away the bottom y = 0.

∫ from 0 to 2 of 2x dy = 2x(2) − 2x(0)

The bottom part is 0.

So it is 4x.

∫ from 0 to 2 of 2x dy = 4x

4 The outer integral

Now the outside integral, in x.

Its limits are numbers.

Integrate each term: the power goes up by 1, and we divide by the new power.

∫ from 0 to 3 of 4x dx = 2x2 from 0 to 3

Put in the top x = 3, then take away the bottom x = 0.

∫ from 0 to 3 of 4x dx = 2(3)2 − 2(0)2

The bottom part is 0.

So it is 18.

∫ from 0 to 3 of 4x dx = 18

5 Check

Let's check in the other order.

x first: 9.

∫ from 0 to 3 of 2x dx = 9

Then y: 18.

The same answer.

Right!

∫ from 0 to 2 of 9 dy = 18

Let's look back.

First: draw it.

Then: find the limits.

Then: the inner integral.

Then: the outer integral.

Last: check.

Answer
∫ from 0 to 3 of 4x dx = 18

Your turn

Try this one yourself, then check:

Find the double integral of ∫ ∫ 2x dA, 0 ≤ x ≤ 2, 0 ≤ y ≤ 2
Show the answer
8

More from Double integrals over rectangles

The whole lesson: Double integrals over rectangles →