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End behavior of f(x) = -x^2(x - 1)(x + 3)

Step by step, with the reason for every step · Polynomial graphs · Algebra 2

Step by step

The question

Question: find the end behavior of f(x) = −x²(x − 1)(x + 3).

f(x) = −x2(x − 1)(x + 3)

1 Find the leading term

The leading term is the part with the biggest power of x.

It decides where the graph goes at the far ends.

leading term: the biggest power of x

Multiply the x's of the brackets, and the −1 in front.

Each bracket gives its x, to its power.

So the leading term is −x⁴.

leading term : −x2 × x × x = −x4

2 Read the ends

The power 4 is even.

So both ends go the same way.

The number in front is negative, so the right end goes down.

power 4: even → ends go the same way
minus in front → right end goes down

Careful!

An even power makes a negative x positive.

So both ends do the same.

Careful: even power: both ends the same way

Far to the right, x gets bigger and bigger.

−x⁴ goes down for ever.

Books write: as x goes to infinity, f(x) goes to minus infinity.

= right end: x → ∞, f(x) → −∞

Far to the left, x is a big negative number.

−x⁴ goes down: f(x) goes to minus infinity.

= left end: x → −∞, f(x) → −∞

We can see it on a small sketch of −x⁴.

Left end down, right end down.

3 Check

Let's check with a big x: x = 10 in −x⁴ gives −10000: big and negative, so down.

x = 10: −104 = −10000 down

And x = −10: −10000, a big negative number: down.

It matches!

x = −10: −(−10)4 = −10000 down

Let's look back.

First: find the leading term.

Then: read the ends.

Last: check.

Answer
= left end: x → −∞, f(x) → −∞

Your turn

Try this one yourself, then check:

end behavior of f(x) = −x2(x − 1)(x + 5)
Show the answer
left down, right down

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