Steply

ξ = {1, 2, ..., 12}, A = {3, 6, 9, 12}, B = {2, 4, 6, 8, 10, 12}…

Step by step, with the reason for every step · Sets · Foundations

Step by step

The question

Question: find n(A ∩ B), when ξ is the numbers 1 to 12, A is {3, 6, 9, 12} and B is {2, 4, 6, 8, 10, 12}.

ξ = {1, 2, …, 12}
A = {3, 6, 9, 12}
B = {2, 4, 6, 8, 10, 12}

1 Read the sets

A set is a list of numbers in curly brackets.

Each number is an element.

ξ is the set of everything we look at.

ξ = everything we look at
∩ = in both
n( ) = how many elements

n(A ∩ B) means: the elements in A and in B: in both.

n means: how many elements.

n(A ∩ B) = = in A and in B: in both

2 Draw the Venn diagram

3 Shade the part

n(A ∩ B) is in A and in B: in both.

On the diagram: the middle.

4 Read the answer

We count the shaded elements: 6, 12.

So n(A ∩ B) = 2.

n(A ∩ B) = 2

5 Check

Let's check some elements against the rule: in A and in B: in both.

They fit.

So it is right!

6: in A, in B; 12: in A, in B

Let's look back.

First: read the sets.

Then: draw the Venn diagram.

Then: shade the part.

Then: read the answer.

Last: check.

Answer
n(A ∩ B) = 2

Your turn

Try this one yourself, then check:

Find ξ = {1, 2, …, 12}
Show the answer
n(A ∩ B) = 2

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