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Estimate √4.1 with a linear approximation

Step by step, with the reason for every step · Linear approximation · Calculus 1

Step by step

The question

Question: estimate √4.1 with a linear approximation.

√4.1 ≈ ?

The function is f(x) = √x.

Near 4.1 there is a friendly number: a = 4.

4 is a perfect square.

f(x) = √x
a = 4

1 The point

Put 4 into f.

We get 2.

The point is (4, 2).

f(4) = √4 = 2

2 The slope there

The slope is the derivative: f′(x) = 1/(2√x).

f′(x) = 12√x

At x = 4, the slope is 1/4.

f′(4) = 12√4 = 12 × 2 = 14

3 The tangent line

The tangent line: start at the height f of a, and go up by the slope times the distance from a.

L(x) = f(a) + f′(a)(x − a)

So L(x) = 2 + 1/4 × (x − 4).

L(x) = 2 + 14(x − 4)

Let's see it.

The curve.

And the tangent line at x = 4.

Near 4, they are almost the same.

4 Estimate

Put 4.1 into L.

L(4.1) = 2 + 14(4.1 − 4)

Careful!

Use the distance from 4: 4.1 minus 4.

Not 4.1 itself.

Careful: not 2 + 14(4.1) ✗

4.1 minus 4 is 0.1.

= 2 + 14 × 0.1

1/4 times 0.1 is 0.025.

= 2 + 0.025

Add it up: 2.025.

= 2.025

So √4.1 ≈ 2.025.

√4.1 ≈ 2.025

5 Check

Let's check with a calculator: √4.1 is 2.02485 and a bit.

Our estimate 2.025 is very close.

Right!

calculator: √4.1 = 2.02485…

Let's look back.

First: the point.

Then: the slope there.

Then: the tangent line.

Then: estimate.

Last: check.

Answer
√4.1 ≈ 2.025

Your turn

Try this one yourself, then check:

Estimate √3.6 ≈ ?
Show the answer
√3.6 ≈ 1.9

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