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Euler path in the graph AB, BC, CD, DA

Step by step, with the reason for every step · Euler paths · Discrete Math

Step by step

The question

Question: find an Euler path in the graph AB, BC, CD, AD.

edges: AB, BC, CD, AD

1 Draw the graph

Each letter is a vertex: a dot.

Each pair is an edge: a line between two vertices.

An Euler path uses every edge exactly once.

An Euler circuit also ends where it started.

Euler path: every edge once
Euler circuit: and back to the start

2 Count the degrees

The degree of a vertex is how many edges touch it.

A has 2.

B has 2.

And so on.

3 Add the degrees

Add the degrees: 8.

That is 2 times the 4 edges, because each edge has two ends.

It always works: the handshake rule.

2 + 2 + 2 + 2 = 8 = 2 × 4 edges

4 Find the odd vertices

The rule: each time we pass through a vertex we use two of its edges, one in and one out.

So only the start and the end can be odd.

0 odd: circuit (start anywhere)
2 odd: path from one odd to the other
more: no Euler path

Careful!

With no odd vertices we can start anywhere, and we come back to the start.

Careful: a circuit ends where it started

5 Walk the route

Start at A.

Go to B: edge 1.

Last, D to A: edge 4.

The circuit: A, B, C, D, A.

= circuit: A, B, C, D, A

6 Check

Check: every edge has exactly one number, 1 to 4, and there are 4 edges.

Right!

numbers 1 to 4, 4 edges: each used once

Let's look back.

First: draw the graph.

Then: count the degrees.

Then: add the degrees.

Then: find the odd vertices.

Then: walk the route.

Last: check.

Answer
= circuit: A, B, C, D, A

Your turn

Try this one yourself, then check:

edges: AB, AC, BD, CD
Show the answer
A, B, D, C, A

More from Euler paths

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