Steply

Evaluate ∫ from 0 to 9 of 2/√x dx

Step by step, with the reason for every step · Improper integrals · Calculus 2

Step by step

The question

Question: find the integral from 0 to 9 of 2 over √x.

∫ from 0 to 9 of 2√x dx =

1 Why is it improper?

Draw the curve.

At x = 0 the curve shoots up for ever: 1/0 has no value.

The area is not closed at the top.

We cannot put in 0.

So we start at a letter, t, just right of 0, and then let t shrink to 0.

x = 0 is not allowed: start at t, then let t → 0

2 Use a limit

The integral is the limit of the integral from t to 9, as t goes to 0 from the right.

∫ from 0 to 9 of 2√x dx = lim t → 0⁺ ∫ from t to 9 of 2√x dx

3 Integrate

The power rule: x to the minus 1/2 becomes x to the 1/2, divided by 1/2.

= lim t → 0⁺ [ 4√x ] from t to 9

4 Let t go

Put in 9, then take away the same with t.

= lim t → 0⁺ (12 − (4√t))

As t shrinks to 0, 4 √t goes to 0.

4√t → 0

The t part goes to 0.

= 12 − 0

5 Decide

The limit is a number: the integral converges to 12.

An area that goes on for ever, but adds up to 12!

= 12

Careful!

Never put 0 in like a number.

We let t shrink and watch where the answer goes.

Careful: not put in 0: 10 ✗

6 Check

Let's check with a calculator: the integral from t = 0.001 is about 11.8735.

Already close to 12.

Right!

t = 0.001: 11.8735

Let's look back.

First: why is it improper?.

Then: use a limit.

Then: integrate.

Then: let t go.

Then: decide.

Last: check.

Answer
Careful: not put in 0: 10 ✗

Your turn

Try this one yourself, then check:

∫ from 0 to 1 of 1√x dx
Show the answer
2

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