Step by step
The question
Question: find the integral from 1 to 2 of 3, all over x² + 3x.
1 Factor the bottom
First factor the bottom.
We need two numbers that multiply to 0 and add to 3: 3 and 0.
2 Split the fraction
Two simple fractions can add up to this one: A over (x + 3), plus B over x.
We find the numbers A and B.
Careful!
ln of the bottom works only when the top is the bottom's derivative.
Here it is not, so we split.
3 Clear the bottoms
Multiply both sides by (x + 3)x.
On the left the bottom goes.
On the right each fraction keeps the other bracket.
4 Find A and B
Put in x = −3: it makes (x + 3) zero, so the B part is gone.
Divide by −3: A = −1.
Put in x = 0: it makes x zero, so the A part is gone.
Divide by 3: B = 1.
5 Integrate
Now the integral is two easy pieces.
One over x minus a number integrates to ln of it, like 1 over x.
No + C: top minus bottom.
6 Top minus bottom
Put in 2, then take away the same with 1, for each piece.
Two logs taken away make one log of a fraction.
The two numbers in front are the same size, 1.
Take it out: one log minus the other is the log of their fraction.
So the integral is ln of 8/5, about 0.470.
7 Check
Let's check: add the two fractions back over one bottom, (x + 3)x.
Open the brackets and add: the top is 3 again.
Right!
Let's look back.
First: factor the bottom.
Then: split the fraction.
Then: clear the bottoms.
Then: find A and B.
Then: integrate.
Then: top minus bottom.
Last: check.