Steply

Evaluate ∫ from 1 to 2 of (4x - 1) dx

Step by step, with the reason for every step · Definite integrals and area · Calculus

Step by step

The question

Question: find the integral from 1 to 2 of 4x − 1.

∫ from 1 to 2 of (4x − 1) dx =

1 The antiderivative

First the antiderivative: add 1 to each power, divide by the new power.

F(x) = 4 × x22 − x

Now we have F(x) = 2 x² − x.

= 2x2 − x

No + C here: in F(b) minus F(a), the two Cs cancel.

no + C here: it cancels

2 Top minus bottom

The rule: put in the top number, then take away the bottom number.

∫ from a to b of f(x) dx = F(b) − F(a)

Write F(x) with 1 and 2 on the bar.

= (2x2 − x) from 1 to 2

Put in 2 first, then take away the same with 1.

= (2(2)2 − 2) − (2(1)2 − 1)

Work out each bracket.

= 6 − 1

Careful!

Top first, then take away the bottom.

The other way gives the wrong sign.

Careful: not F(1) − F(2) ✗

So the integral is 5.

= 5

3 Check

Let's check with geometry.

Under a straight line the shape is a trapezoid: heights 3 and 7, width 1.

Its area is 5.

The same!

Right!

trapezoid: 3 + 72 × 1 = 5

Let's look back.

First: the antiderivative.

Then: top minus bottom.

Last: check.

Answer
= 5

Your turn

Try this one yourself, then check:

∫ from 0 to 2 of (4x − 1) dx
Show the answer
6

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