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Exterior angle 120, inside angles 70 and x

Step by step, with the reason for every step · Exterior angle of a triangle · Geometry

Step by step

The question

Question: if the exterior angle is 120° and the far inside angles are 70° and x°, what is x?

outside 120°, inside 70° and x°

The exterior angle is outside the triangle, on the pushed-out side.

1 Use the rule

outside angle = the two far inside angles

The exterior angle is the two far inside angles added together.

So 70 + x = 120.

= 70 + x = 120

Careful!

The outside angle is not inside the triangle.

It does not go in the 180° sum.

Careful: not 70 + x + 120 = 180 ✗

2 Remove the 70

We want x by itself.

The 70 is in the way.

To remove 70, we take away 70.

We do it on both sides.

Why both sides?

The = sign means both sides are the same amount.

If we change only one side, they are not the same any more.

70 + x − 70 = 120 − 70

70 and − 70 make zero.

Cross them out.

120 − 70 = 50.

120 − 70 = 50

So x = 50!

x = 50

3 Check

Let's check: with x = 50, the inside angles are 70° and 50°.

Together 120°, the outside angle.

So the answer is right!

inside 70° and 50°: 70 + 50 = 120 = outside 120°

Let's look back.

First: use the rule.

Then: remove the 70.

Last: check.

Answer
x = 50

Your turn

Try this one yourself, then check:

outside 80°, inside 70° and x°
Show the answer
x = 10

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