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f(x) = x + 5, g(x) = 3x, find (f/g)(x)

Step by step, with the reason for every step · Dividing functions f/g · Algebra 2

Step by step

The question

Question: find (f/g)(x) for f(x) = x + 5 and g(x) = 3x.

f(x) = x + 5
g(x) = 3x

(f/g)(x) means f of x divided by g of x.

We write it as a fraction: f on top, g at the bottom.

(f/g)(x) = f(x)g(x)

1 Put the rules in

Each rule goes in as one piece: (x + 5)/(3x).

(f/g)(x) = x + 53x

2 Find what x can't be

We can never divide by 0.

So the bottom, g of x, can never be 0.

÷ 0: not allowed → g(x) ≠ 0

Careful!

The answer is not only the fraction.

x = 0 makes the bottom 0, so we must say it is not allowed.

Careful: write the x that g can't be

Which x makes 3x zero?

We solve 3x = 0.

3x = 0

3 Remove the 3

3x means 3 times x.

We want just x.

To remove times 3, we divide by 3.

We do it on both sides, so they stay equal.

3x3 = 03

3 divided by 3 is 1.

So just x is left.

0 divided by 3 is 0.

03 = 0

So x = 0!

x = 0

So (f/g)(x) = (x + 5)/(3x), with x ≠ 0.

(f/g)(x) = x + 53x, x ≠ 0

4 Check

Let's check with a number: x = 1.

f of 1 is 6, g of 1 is 3.

Divided: 2.

f(1)g(1) = 63 = 2

That is our fraction at x = 1.

It works!

Let's look back.

First: put the rules in.

Then: find what x can't be.

Then: remove the 3.

Last: check.

Answer
(f/g)(x) = x + 53x, x ≠ 0

Your turn

Try this one yourself, then check:

f(x) = x + 3, g(x) = 3x, find (f/g)(x)
Show the answer
(f/g)(x) = x + 33x, x ≠ 0

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