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Factor completely x^4 + 2x^3 - 8x^2

Step by step, with the reason for every step · Factoring completely · Algebra 1

Step by step

The question

Question: factor completely x⁴ + 2x³ − 8x².

Completely means: until no part can be factored any more.

x4 + 2x3 − 8x2

1 Common factor first

Every term has x².

So the common factor is x².

every term has x2

We divide every term by it.

What is left goes in the bracket.

x4 ÷ x2 = x2
2x3 ÷ x2 = 2x
−8x2 ÷ x2 = −8

So it is x²(x² + 2x − 8).

= x2(x2 + 2x − 8)

2 Count the terms

The bracket has 3 terms.

With 3 terms we look for two numbers that multiply to c and add to b.

We need two numbers.

They multiply to −8, and they add to 2.

? × ? = −8
? + ? = 2

They multiply to a minus number, so one number is plus and one is minus.

They add to a plus number, so the bigger one is plus.

× is − → one +, one −; bigger one +

We list the pairs that make 8, smallest first.

We take the smaller from the bigger.

We need 2.

2 and 4 give 2.

Yes!

With the signs: −2 and 4.

1 × 8: 8 − 1 = 7
2 × 4: 4 − 2 = 2 ✓

So we get x²(x − 2)(x + 4).

= x2(x − 2)(x + 4)

3 Check each bracket

Brackets like x − 2 have just x and a number.

They can't be factored.

x − 2, x + 4: just x and a number

No bracket can be factored any more.

So we are done.

Careful!

Don't forget the common factor x² in the answer.

Careful: not (x² + 2x − 8) ✗

4 Check

Let's check: we multiply it back out.

Each part of one bracket times each part of the other.

Check: (x − 2)(x + 4) = x2 + 4x − 2x − 8
= x2 + 2x − 8

Then the common factor times every part.

x2(x2 + 2x − 8) = x4 + 2x3 − 8x2

We get x⁴ + 2x³ − 8x² again.

So it is right!

Let's look back.

First: common factor first.

Then: count the terms.

Then: check each bracket.

Last: check.

Answer
x − 2, x + 4: just x and a number

Your turn

Try this one yourself, then check:

Factor completely 3x4 − 18x3 + 27x2
Show the answer
3x2(x − 3)2

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