Step by step
The question
Question: solve y³ − 3y² + 2y = 0.
The right side is 0 already.
1 Factor completely
Common factor first.
Every term has y.
So we take out y.
So it is y(y² − 3y + 2) = 0.
Careful!
Don't divide both sides by y.
Then the answer y = 0 would be lost.
Now the bracket.
We need two numbers.
They multiply to 2, and they add to −3.
They multiply to a plus number, so the two numbers have the same sign.
They add to a minus number, so both are minus.
We list the pairs that make 2, smallest first.
We add each pair.
We need 3.
1 and 2 give 3.
Yes!
With the signs: −1 and −2.
So it is y(y − 1)(y − 2) = 0.
2 Each factor is 0
Some numbers multiply to 0.
That only happens if one of them is 0.
So we make each factor 0.
Each factor with x gives a small equation.
y = 0 is done already.
In y − 1 = 0, we add 1 on both sides.
In y − 2 = 0, we add 2 on both sides.
So y = 0, y = 1 and y = 2.
Three answers.
3 Check
Let's check: put each answer into y³ − 3y² + 2y = 0.
First y = 0.
Now y = 1.
Now y = 2.
We get 0 every time.
So all three answers are right!
Let's look back.
First: factor completely.
Then: each factor is 0.
Last: check.