Steply

Factor y^3 - 3y^2 + 2y = 0

Step by step, with the reason for every step · Solving by factoring · Algebra 1

Step by step

The question

Question: solve y³ − 3y² + 2y = 0.

y3 − 3y2 + 2y = 0

The right side is 0 already.

y3 − 3y2 + 2y = 0

1 Factor completely

Common factor first.

Every term has y.

So we take out y.

common factor: y

So it is y(y² − 3y + 2) = 0.

y(y2 − 3y + 2) = 0

Careful!

Don't divide both sides by y.

Then the answer y = 0 would be lost.

Careful: don't divide by y. We would lose y = 0.

Now the bracket.

We need two numbers.

They multiply to 2, and they add to −3.

? × ? = 2, ? + ? = −3

They multiply to a plus number, so the two numbers have the same sign.

They add to a minus number, so both are minus.

× is + → same signs: both −

We list the pairs that make 2, smallest first.

We add each pair.

We need 3.

1 and 2 give 3.

Yes!

With the signs: −1 and −2.

1 × 2: 1 + 2 = 3 ✓

So it is y(y − 1)(y − 2) = 0.

y(y − 1)(y − 2) = 0

2 Each factor is 0

Some numbers multiply to 0.

That only happens if one of them is 0.

So we make each factor 0.

A × B × C = 0 → A = 0 or B = 0 or C = 0

Each factor with x gives a small equation.

y = 0 or y − 1 = 0 or y − 2 = 0

y = 0 is done already.

In y − 1 = 0, we add 1 on both sides.

In y − 2 = 0, we add 2 on both sides.

y = 0 or y = 1 or y = 2

So y = 0, y = 1 and y = 2.

Three answers.

3 Check

Let's check: put each answer into y³ − 3y² + 2y = 0.

First y = 0.

y = 0: 03 − 3(0)2 + 2(0) = 0 + 0 + 0 = 0

Now y = 1.

y = 1: 13 − 3(1)2 + 2(1) = 1 − 3 + 2 = 0

Now y = 2.

y = 2: 23 − 3(2)2 + 2(2) = 8 − 12 + 4 = 0

We get 0 every time.

So all three answers are right!

Let's look back.

First: factor completely.

Then: each factor is 0.

Last: check.

Answer
y = 0 or y = 1 or y = 2

Your turn

Try this one yourself, then check:

Solve y3 − 11y2 + 30y = 0
Show the answer
y = 0 or y = 5 or y = 6

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