Steply

Find d/dx ∫ from 0 to x^2 of (t + 1) dt

Step by step, with the reason for every step · The Fundamental Theorem, part 1 · Calculus 1

Step by step

The question

Question: find the derivative of ∫ from 0 to x² of (t + 1) dt.

ddx∫ from 0 to x² of (t + 1) dt =

1 The rule

The rule: the derivative of the area from a to x is the function at x.

Just put x in place of t.

ddx∫ from a to x of f(t) dt = f(x)

Why?

Look at the area under f from 0 to x.

Move x a tiny bit to the right.

The area grows by a thin strip.

Its height is f(x).

So the area grows at the rate f(x).

2 Put the top in place of t

The top is not just x: it is x².

Call it u.

Its slope is u′.

top: u = x2, u′ = 2x

The chain rule: put u in place of t, then multiply by u′.

ddx∫ from 0 to x² of (t + 1) dt = f(u) × u′

Put x² in place of t, times 2x.

= (x2 + 1) × 2x

Careful!

Do not stop at f of u.

The top is x², so we must multiply by its slope, 2x.

Careful: not (x2 + 1) ✗

Multiply it out: 2 x³ + 2x.

= 2x3 + 2x

3 Check

Let's check at x = 1.

Our answer gives 4.

answer at x = 1: 4

Now the slope of the area function F between x = 1 and 1.001, with a calculator: about 4.004.

The same!

Right!

F(1.001) − F(1)0.001 ≈ 4.004

Let's look back.

First: the rule.

Then: put the top in place of t.

Last: check.

Answer
= 2x3 + 2x

Your turn

Try this one yourself, then check:

ddx∫ from 1 to x² of (4t + 2) dt
Show the answer
8x3 + 4x

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