Steply

Find the area of R

Step by step, with the reason for every step · AP Calculus AB Practice Exam 1 · AP Calculus AB

Step by step

The question

Question: find the area between y = 4x − x² and the x-axis.

y = 4x − x2

1 Draw the region

Draw the curve first.

Where does it cross the x-axis?

Where y is 0.

4x − x² = 0

Factor it.

Every term has −x, so we take it out.

−x(x − 4) = 0

So it crosses at x = 0 and x = 4.

x = 0 or x = 4

The area we want is shaded: under the curve, above the x-axis, from 0 to 4.

This area is the integral from 0 to 4.

area = ∫ from 0 to 4 of (4x − x2) dx

2 The antiderivative

First the antiderivative: add 1 to each power, divide by the new power.

F(x) = 4 × x22 − x33

Now we have F(x) = 2 x² − x³ over 3.

= 2x2 − x33

No + C here: in F(b) minus F(a), the two Cs cancel.

no + C here: it cancels

3 Top minus bottom

The rule: put in the top number, then take away the bottom number.

∫ from a to b of f(x) dx = F(b) − F(a)

Write F(x) with 0 and 4 on the bar.

= (2x2 − x33) from 0 to 4

Put in 4 first, then take away the same with 0.

= (2(4)2 − 433) − (2(0)2 − 033)

First the powers and the times.

= (32 − 643) − (0 − 0)

Then each bracket: the first is 32/3, the second is 0.

= 323 − 0

Careful!

Top first, then take away the bottom.

The other way gives the wrong sign.

Careful: not F(0) − F(4) ✗

So the area is 32/3 square units.

area = 323 square units

4 Check

Let's check F: its derivative is 4x − x², the function we started with.

Right!

F′(x) = 4x − x2

Let's look back.

First: draw the region.

Then: the antiderivative.

Then: top minus bottom.

Last: check.

Answer
area = 323 square units

Your turn

Try this one yourself, then check your answer:

Find the area between y = 4 − x2 and the x-axis
Show the answer
area = 323 square units

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