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Find the sum 8 + 4 + 2 + 1 + ...

Step by step, with the reason for every step · Series · Algebra 2

Step by step

The question

Question: find the sum 8 + 4 + 2 + 1 + and so on.

The dots at the end mean: it goes on forever.

8 + 4 + 2 + 1 + ...

1 Find the ratio

2 Look at the sums

1/2 is less than 1.

Each new term is smaller.

So the sums settle down near one number.

|r| = 12 < 1

Let's add the terms one at a time, and write each running sum: 8, 12, 14, and so on.

3 Use the sum rule

In the sum rule, r to the power n gets closer and closer to 0.

So it drops out, and the sum is the first term over 1 minus r.

S = a11 − r

Careful!

The terms go on forever, but the sum does not: each term is smaller than the one before.

Careful: forever, but the sum is not endless

Put in a₁ = 8 and r = 1/2.

S = 81 − 12

1 − 1/2 is 1/2.

So we divide by 1/2.

S = 8 ÷ 12

Dividing by 1/2 is times its flip, 2.

S = 8 × 2

So the sum is 16.

S = 16

4 Check

Let's check: we keep adding terms.

The running sums are 15.75, 15.875, 15.938.

sums: 15, 15.5, 15.75, 15.875, 15.938, ...

They get closer and closer to 16.

It works!

closer and closer to 16

Let's look back.

First: find the ratio.

Then: look at the sums.

Then: use the sum rule.

Last: check.

Answer
S = 16

Your turn

Try this one yourself, then check:

find the sum 18 + 6 + 2 + 23 + ...
Show the answer
27

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