Steply

Graph y = 1/3|x| - 2 from y = |x|

Step by step, with the reason for every step · Graph stretches · Algebra 2

Step by step

The question

Question: graph y = one third times |x|, − 2, from y = |x|.

y = 13|x| − 2

We know the graph of y = |x|.

It is a V.

we know: y = |x|

1 Read the changes

The one third in front makes every y one third as big.

Smaller y's: the graph gets wider and flatter.

13 in front → every y × 13

Careful!

A number bigger than 1 makes it narrower.

A number between 0 and 1 makes it wider.

Careful: a number between 0 and 1 in front: wider, not narrower

Outside, at the end, − 2 takes 2 away from every y.

So the graph moves down 2.

− 2 outside → down 2

2 Start from y = |x|

Draw the grid.

Draw y = |x| first.

It goes through (−3, 3), (0, 0) and (3, 3).

3 Shrink the y's

(−3, 3): one third of 3 is 1.

It goes to (−3, 1).

(0, 0) stays: one third of 0 is 0.

(3, 3): one third of 3 is 1.

It goes to (3, 1).

4 Move the corner

The corner moves down 2.

Every point moves the same way.

The new points: (−3, −1), (0, −2) and (3, −1).

5 Draw the new graph

Join them with the same shape, wider.

This is the new graph.

6 Check

Let's check: put x = 3 in the new rule.

One third of 3 is 1, minus 2 is −1.

We get the point (3, −1).

It works!

x = 3: y = 13|3| − 2 = 13 × 3 − 2 = 1 − 2
= −1

Let's look back.

First: read the changes.

Then: start from y = |x|.

Then: shrink the y's.

Then: move the corner.

Then: draw the new graph.

Last: check.

Answer
− 2 outside → down 2

Your turn

Try this one yourself, then check:

graph y = 13|x| − 3 from y = |x|
Show the answer
corner (0, −3), through (3, −2)

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