Steply

Graph y = 1/3x - 1 and y = -x + 3

Step by step, with the reason for every step · Systems by graphing · Algebra 1

Step by step

The question

Question: solve by graphing y = (1/3)x − 1 and y = −x + 3.

① y = 13x − 1 and ② y = −x + 3

The answer is a point that is on both lines.

So we draw both lines and see where they meet.

answer = the point on both lines

1 Graph line ①

Draw the grid.

The x-axis goes across.

The y-axis goes up and down.

They meet at 0.

That point is called the origin.

In ①, b = −1.

Start on the y-axis at −1.

m = 1/3.

Go right 3,

then up 1.

Dot.

Join the dots with a straight line.

2 Graph line ②

In ②, b = 3.

Start on the y-axis at 3.

m = −1.

As a fraction: −1/1.

Go right 1,

then down 1.

Dot.

Join the dots with a straight line.

3 Where they meet

The lines meet at one point.

It is on the x-axis: x = 3.

Go straight across to the y-axis: y = 0.

So x = 3 and y = 0, both at the same time: the point (3, 0).

(x, y) = (3, 0)

4 Check in both

Let's check: put x = 3 and y = 0 into both equations.

First ①.

① y = 13(3) − 1 = 1 − 1 = 0

We get 0.

That is y.

It works.

Now ②.

② y = −3 + 3 = 0

We get 0.

That is y.

It works.

(3, 0) is on both lines.

So the answer is right!

Let's look back.

First: graph line ①.

Then: graph line ②.

Then: where they meet.

Last: check in both.

Answer
(x, y) = (3, 0)

Your turn

Try this one yourself, then check:

① y = 13x + 1 and ② y = −x + 5
Show the answer
(x, y) = (3, 2)

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