Steply

Graph y = 2√x + 1 from y = √x

Step by step, with the reason for every step · Graph stretches · Algebra 2

Step by step

The question

Question: graph y = 2√x + 1 from y = √x.

y = 2√x + 1

We know the graph of y = √x.

It is half a U, lying on its side.

we know: y = √x

1 Read the changes

The 2 in front makes every y 2 times as big.

The graph gets steeper.

2 in front → every y × 2

Outside, at the end, + 1 adds 1 to every y.

So the graph moves up 1.

+ 1 outside → up 1

2 Start from y = √x

Draw the grid.

Draw y = √x first.

It goes through (0, 0), (1, 1) and (4, 2).

3 Move the points

The start point (0, 0) moves up 1.

(0, 0) goes to (0, 1).

(1, 1) goes to (1, 3).

(4, 2) goes to (4, 5).

4 Draw the new graph

Join the new points with the same shape.

This is y = 2√x + 1.

5 Check

Let's check.

Put x = 0 in the new rule.

We get y = 1: the point (0, 1) we drew.

x = 0: y = 2√0 + 1 = 2 × 0 + 1 = 1

And x = 4 gives y = 5: the point (4, 5).

x = 4: y = 2√4 + 1 = 2 × 2 + 1 = 5

Let's look back.

First: read the changes.

Then: start from y = √x.

Then: move the points.

Then: draw the new graph.

Last: check.

Answer
+ 1 outside → up 1

Your turn

Try this one yourself, then check:

graph y = 2√x + 3 from y = √x
Show the answer
start point (0, 3), through (4, 7)

More from Graph stretches

The whole lesson: Graph stretches →