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Graph y = csc x in degrees

Step by step, with the reason for every step · Graphs of sec, csc and cot · Trigonometry

Step by step

The question

Question: graph y = csc x.

The x values are in degrees.

y = csc x

1 Write it as 1 over

csc x means 1 over sin x.

csc goes with sin: each one is sin turned upside down.

csc x = 1sin x

Careful!

csc x is 1 over sin x.

It is not the inverse sine, sin to the minus 1.

That is a different thing.

Careful: csc x = 1 ÷ sin x, not sin−1 x

2 Draw the helper graph

Draw the grid.

A mark every 90°: a quarter of the period.

Our helper is y = sin x.

Its amplitude is 1, and its period is 360° over 1: 360°.

y = sin x
period = 360°1 = 360°

We draw the helper wave lightly, dashed.

csc will be built from it.

3 Find the gaps

Where the helper is 0, csc is 1/0.

We can never divide by 0: there is a gap.

We draw a dashed line there: an asymptote.

The helper crosses the x-axis at 0°, 180° and 360°, and so on.

sin x = 0: x = 0°, 180°, 360°, ...

4 Find the turning points

Where the helper is at its top or bottom, sin x is 1 or −1.

1/1 is 1, and 1 over −1 is −1: the value stays the same.

csc touches the helper there.

1 ÷ 1 = 1, 1 ÷ (−1) = −1

5 Draw the U shapes

Between two gaps, the graph is a U.

It starts at the turning point.

As the helper gets closer to 0, 1 over it gets bigger and bigger: up to the gap.

Where the helper is below the axis, the U opens down.

6 Check

Let's check one more point: x = 30°.

sin 30° is one half.

1 over one half is 2.

So y is 2: the point is on the U.

Right!

x = 30°: sin 30° = 12, y = 1 ÷ 12 = 2

Let's look back.

First: write it as 1 over.

Then: draw the helper graph.

Then: find the gaps.

Then: find the turning points.

Then: draw the U shapes.

Last: check.

Answer
csc x = 1sin x

Your turn

Try this one yourself, then check:

y = sec x
Show the answer
period 360°, gaps where cos x = 0

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