Steply

Graph y = x + 2 and 2y - 2x = 4

Step by step, with the reason for every step · Systems by graphing · Algebra 1

Step by step

The question

Question: solve by graphing y = x + 2 and 2y − 2x = 4.

① y = x + 2 and ② 2y − 2x = 4

The answer is a point that is on both lines.

So we draw both lines and see where they meet.

answer = the point on both lines

1 Crossing points of ②

On the x-axis, y = 0.

Put 0 in place of y.

2 × 0 − 2x = 4

2 times 0 is 0.

0 minus 2x is −2x.

−2x = 4

−2x means −2 times x.

We want just x.

To remove times −2, we divide by −2.

We do it on both sides, so they stay equal.

−2x−2 = 4−2

−2 divided by −2 is 1.

So just x is left.

Plus over minus is minus.

4 divided by −2 is −2.

4−2 = −2

So x = −2.

x = −2

On the y-axis, x = 0.

Put 0 in place of x.

2y − 2 × 0 = 4

2 times 0 is 0.

Taking away 0 changes nothing.

2y = 4

2y means 2 times y.

We want just y.

To remove times 2, we divide by 2.

We do it on both sides, so they stay equal.

2y2 = 42

2 divided by 2 is 1.

So just y is left.

4 divided by 2 is 2.

42 = 2

So y = 2.

So line ② crosses the axes at (−2, 0) and (0, 2).

y = 2

2 Graph line ①

Draw the grid.

The x-axis goes across.

The y-axis goes up and down.

They meet at 0.

That point is called the origin.

In ①, b = 2.

Start on the y-axis at 2.

m = 1.

As a fraction: 1/1.

Go right 1,

then up 1.

Dot.

Join the dots with a straight line.

3 Graph line ②

Put the two crossing points on the grid,

and join them.

4 Where they meet

Both equations make the same line.

They meet everywhere.

So every point on the line works.

The same line: every point on it works.

Let's look back.

First: crossing points of ②.

Then: graph line ①.

Then: graph line ②.

Last: where they meet.

Answer
The same line: every point on it works.

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