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Integrate ∫ (2x + 1) dx

Step by step, with the reason for every step · Antiderivatives · Calculus

Step by step

The question

Question: find ∫ (2x + 1) dx, the antiderivative of 2x + 1.

∫ (2x + 1) dx =

1 The rule

The power rule takes 1 off the power, and the power comes down in front.

x3 → 3x2 (derivative)

Backwards, we undo both: add 1 to the power, then divide by the new power.

∫ and dx just mean: find the function whose derivative this is.

∫ xn dx = xn + 1n + 1 + C

Why + C?

A number alone has slope 0.

So any number could have been there.

We write C for it.

+ C: any number; its derivative is 0

Careful!

Every antiderivative ends with + C.

Without it, the answer is not complete.

Careful: never forget + C

2 Each term

Use it on each term.

A number alone, like 5, comes from 5x: it gets an x.

= 2 × x22 + x + C

Divide the numbers where we can: 2 divided by 2 is 1.

2 ÷ 2 = 1

So the answer is x² + x + C.

= x2 + x + C

3 Check

Let's check: take the derivative of our answer.

The C gives 0.

We get 2x + 1: the question again.

Right!

(x2 + x + C)′ = 2x + 1

Let's look back.

First: the rule.

Then: each term.

Last: check.

Answer
= x2 + x + C

Your turn

Try this one yourself, then check:

Find ∫ (6x + 6) dx
Show the answer
3x2 + 6x + C

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